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Ber [7]
3 years ago
6

What is the slope of (7,-30) and (11,-54)

Mathematics
1 answer:
timama [110]3 years ago
5 0

Answer:

-6

Step-by-step explanation:

we just need to do the step slope=(y2-y1)/(x2-x1)

so slope =-30-(-54)/(7-11)=24/-4=-6

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Read 2 more answers
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

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3 years ago
Hiii how are you guys doing if you answer this I’ll give you points and make you brainly or what ever it’s called and how do you
baherus [9]

Answer:

Hi how is your day going?

Step-by-step explanation:

I have some jokes and I hope you like them.

Knock Knock.

Who's There?

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Scold who?

Scold outside, let me in!

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Who's there?

Tank.

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