Here, the given equation is,
x^2+y^2+px+6y-3=0
By copairing it with x^2+y^2+2gx+2fy+c=0, we get,
2g=p or, g=p/2
2f=6 or, f=3
c=-3
now the radius is,
r^2=g^2+f^2-c
or, 4^2=(p/2)^2 +3^2 -(-3)
or, 16= p^2/4 +9+3
or, 16-9-3=p^2/4
or p^2/4=4
or, p^2=4×4
or p^2=4^2
or p=4
therefore the rewuired value of p is 4.
Answer:
8 - 2x
Step-by-step explanation:
Let x be the unknown number
difference is subtraction
8 - 2x
We will calculate this by using ratios and because these two triangles are similar, which is very important.
Explanation:
We see that the FG = 9 corresponds to the VU = 21. Therefore, FH = 18 corresponds to the UW = x.
9 : 21 = 18 : x
x = (21*18)/9
x = 378/9
x = 42.
The correct answer is B. 42.
Answer:
Step-by-step explanation:
<u>Two ways to solve</u>
1.) Expand each term in the equation
- 7x = x · x · x · x · x · x · x
- 6x = x · x · x · x · x · x
- Count all the x’s ⇒ There are 13 x’s ⇒ 13x
2.) Add the coefficients
Hence,
Answer = 13x
