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KiRa [710]
3 years ago
10

Given the function h(x), determine the functions which correctly decompose h(x) into component functions f(x) and g(x) so that h

(x) = f(g(x)).
$\tex$ h(x) = \sqrt{7x+2} - 10
Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

\text{Hi there! :)}

\large\boxed{g(x) = 7x + 2\text{ , } f(x) = \sqrt{x}  - 10}

\text{h(x) = f(g(x)), so determine what g(x) was substituted into f(x):}\\\\\text{Given the equation } h(x) = \sqrt{7x +2}- 10:\\\\\text{In the part of the equation with a variable, we see that "7x + 2" is in a square root:}

\text{Therefore, we can say that g(x) = 7x + 2:}\\\\\text{If h(x) = f(7x + 2), then f(x) must be:}\\\\f(x) = \sqrt{x} - 10

\text{The respective functions would be:}\\\\g(x) = 7x + 2\\\\f(x) = \sqrt{x}  - 10

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If alpha and beta are the zeroes of the polynomial f(x)= xsquare -8x +gamma such that alpha - beta = 2 find the value of gamma.
Komok [63]

Answer:

Γ = 15

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product of zeros = αβ = \frac{c}{a} = Γ

Given α - β = 2 , then

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α² - 2αβ + β² = 4 → (1)

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(α + β)² = 8²

α² + 2αβ + β² = 64 → (2)

Add (1) and (2) term by term

2α² + 2β² = 68 ( divide through by 2 )

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Substitute α² + β² = 34 into (1)

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- 2αβ = - 30 ( divide both sides by - 2 )

αβ = 15

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4 0
3 years ago
the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing
Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

266 = 6 + 5w

260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

#SPJ1

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2 years ago
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