The answer for that is m=-2
25% of 36 is 9 so I’m guessing the answer is 9?
Answer:
maximum height of the arrow will be 408 m
Step-by-step explanation:
We have given the function of height as ![h(t)=-16t^2+160t+8](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2B160t%2B8)
We know that first derivative of height will be velocity
So first derivative of height
![\frac{dh}{dt}=-32t+160](https://tex.z-dn.net/?f=%5Cfrac%7Bdh%7D%7Bdt%7D%3D-32t%2B160)
![v(t)=-32t+160](https://tex.z-dn.net/?f=v%28t%29%3D-32t%2B160)
We know that at maximum height velocity will be zero
![-32t+160=0](https://tex.z-dn.net/?f=-32t%2B160%3D0)
t = 5 sec
Sp arrow will be at maximum height at t = 5 sec
So height at t = 5 sec will be
![h(5)=-16\times 5^2+160\times 5+8=408m](https://tex.z-dn.net/?f=h%285%29%3D-16%5Ctimes%205%5E2%2B160%5Ctimes%205%2B8%3D408m)
So maximum height of the arrow will be 408 m