Answer:
There are 64,000 possible codes. Jillian is incorrect, since he added the possible options in each trial, instead of multiplied them(he did 40+40+40 instead of 40*40*40).
Step-by-step explanation:
From 0 to 39, there are 40 numbers.
The code has three values:
V1 - V2 - V3
When we have n trials with m possible options, the total number of opitons is:
In this question:
3 trials(values), with 40 options. So
There are 64,000 possible codes. Jillian is incorrect, since he added the possible options in each trial, instead of multiplied them(he did 40+40+40 instead of 40*40*40).
P.Theorem says a^2 + b^2 = c^2
We know c^2 is 10, the diagonal length, and one leg we will call a^2 is 9
10^2 - 9^2 = b^2 (width)
Width is 4.36
In a rhombus, the diagonals meet at right-angles, and they bisect each other, namely they cut each other in half, check the picture below.
thus we can use the pythagorean theorem to get one side, keeping in mind that, slanted as it may be, all sides in a rhombus are equal in length.
We are given that
An ion has a charge of +7
and a neutral has charge always 0
so, change is charge = ion charge - neutral change
so, we can plug values
change is charge = +7 -0
change is charge = 7
so, option-C..................Answer
