Your answer would be 6.659 hope this helpedddd
Answer:
$9,393.78
Step-by-step explanation:
Using the equation:
A = P(1+r)^t
Where,
A = final amount
P = initial amount = $6,600
r = rate of increase = 4% = 0.04
t = time in years = 9 years (2012-2021)
A = 6,600(1 + 0.04)^9
= 6,600(1.04)^9
= 6,600(1.4233)
= 9,393.78
A = $9,393.78
Answer:
The solution set can be given as:
Step-by-step explanation:
Given function:
To find the domain of the function in set notation.
Solution:
For the function 
to exist the denominator must be ≠ 0
We have the denominator 
which cannot be = 0.
Thus, we can find the domain of the function using the above relation.
The function will not exist when:
Solving for 
Subtracting both sides by 6.
Dividing both sides by 2.
∴ 
Thus, the function will not exist at . This means it has all real number solutions except -3.
The solution set can be given as:
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
Like on a test if you get extra credit.
Step-by-step explanation:
