A) side-side-side triangle similarity postulate
2 answers:
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Answer:
a) 0.2725
b) 0.7275
c) 0.8948
Step-by-step explanation:
This is a binomial distribution probability problem. The formula is:
Where
n is the number of trials [here we are taking 8 person, so n = 8]
x is what we are looking for [in the problem]
p is the probability of success [ 15%, so p = 0.15
q is the probability of failure [q = 1-p = 0.85]
Now,
a)
We are looking for "no one" did fling, so x = 0
Let's put into formula and find out the probability:
So, the probability that no one has done a one-time fling is 0.2725
b)
Atleast 1 person means P(x ≥ 1).
This can be found by:
P(x ≥ 1) = 1 - P(x=0) = 1 - 0.2725 = 0.7275
THus, Probability that at least one person has done a one-time fling is 0.7275
c)
No more than 2 people means P (x≤2).
This is essentially
P ( x ≤ 2 ) = P(x=0) + P(x=1) + P(x=2)
P ( x = 0 ) is found in part (a), which is 0.2725
P (x = 1 ) and P(x=2) can be found using formula:
and
Thus,
P ( x ≤ 2 ) = P(x=0) + P(x=1) + P(x=2) = 0.2725 + 0.3847 + 0.2376 = 0.8948
(C) 6 + 3√3
<u>Explanation:</u>
Area of the square = 3
a X a = 3
a² = 3
a = √3
Therefore, QR, RS, SP, PQ = √3
ΔBAC ≅ ΔBQR
Therefore,
In ΔBAC, BA = AC = BC because the triangle is equilateral
So,
BQ = √3
So, BQ, QR, BR = √3 (equilateral triangle)
Let AP and SC be a
So, AQ and RC will be 2a
In ΔAPQ,
(AP)² + (QP)² = (AQ)²
(a)² + (√3)² = (2a)²
a² + 3 = 4a²
3 = 3a²
a = 1
Similarly, in ΔRSC
(SC)² + (RS)² = (RC)²
(a)² + (√3)² = (2a)²
a² + 3 = 4a²
3 = 3a²
a = 1
So, AP and SC = 1
and AQ and RC = 2 X 1 = 2
Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR
Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3
Perimeter = 6 + 3√3
Therefore, the perimeter of the triangle is 6 + 3√3