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tester [92]
3 years ago
14

Can u answer all three pls

Mathematics
2 answers:
Kipish [7]3 years ago
7 0
2nd question is 8x4=32 because perimeter of the square is equal to dimension x4 or side + side+side + side . I hope you understand that:)
faust18 [17]3 years ago
5 0

Answer:

1. 28ft

2. 26ft

3. 20ft

Step-by-step explanation:

here ya go

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For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
Elina [12.6K]

Answer:

<em>C.</em> (5-\frac{1}{2})^6

Step-by-step explanation:

Given

15(5)^2(-\frac{1}{2})^4

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

Sum = 2 + 4

Sum = 6

Each term of a binomial expansion are always of the form:

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

Where n = the sum above

n = 6

Compare 15(5)^2(-\frac{1}{2})^4 to the above general form of binomial expansion

(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......

Substitute 6 for n

(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

By direct comparison of

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

and

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

We have;

^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4

Further comparison gives

^nC_r = 15

a^{n-r} =(5)^{6-4}

b^r= (-\frac{1}{2})^4

[Solving for a]

By direct comparison of a^{n-r} =(5)^{6-4}

a = 5

n = 6

r = 4

[Solving for b]

By direct comparison of b^r= (-\frac{1}{2})^4

r = 4

b = \frac{-1}{2}

Substitute values for a, b, n and r in

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

Solve for ^6C_4

(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em>(5-\frac{1}{2})^6<em />

3 0
3 years ago
Composition of functions
astra-53 [7]
For example, in the composition of(f g)(x) = f(g(x)), we need to replace each x found in f(x), the outside function, with g(x), the inside function. Step 3: Simplify the answer. Examples – Now let's use the steps shown above to work through some examples. Example 1: If f(x) = –4x + 9 and g(x) = 2x – 7, find(f g)(x).
7 0
3 years ago
LA and B are vertical angles. If mZA = then find the value of x. (7x – 27) and m B = (3x + 29)°,
zhuklara [117]

we know that

Vertical angles are congruent angles

that means

substitute the given values

(7x – 27)=(3x + 29)

solve for x

7x-3x=29+27

4x=56

x=14

part b)

We know that

Supplementary angles are angles that their sum is equal to 180 degrees

so

A+B=180

substitute the given values

5x+25+x+17=180

solve for x

6x+42=180

6x=180-42

6x=138

x=23

Find the measure of Angle A

4 0
1 year ago
14+13y=20y-21 work for answer?
andre [41]

Answer:

Y= 5

Step-by-step explanation:

14+13Y=20Y-21

    -13y  -13y

14=7y-21

+21      +21

35/7=7y/7

y=5

 

8 0
3 years ago
Read 2 more answers
Someone please help!!! I need this asap! I will mark brainliest if correct!
Natali5045456 [20]

Answer:

choice 4) SAS

Step-by-step explanation:

5 0
2 years ago
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