Answer:
Simlyifying, you get 21x^2
Step-by-step explanation:
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Answer:
b = 11
Step-by-step explanation:
the standard form of a quadratic equation is ax² + bx + c = 0 ( a ≠ 0 )
given
x² + 28 = - 11x ( add 11x to both sides )
x² + 11x + 28 = 0 ← in standard form
with b = 11
Answer:
y>-3
Step-by-step explanation:
Distributive property
18y-21>-75
18y-21>-75
+21>+21
18y>-54
Divide each side by 18
y>-3