The probability of a student taking a math class or a physics class is
when the probability of a student taking a math class is
, the probability of taking a physics class is
, and the probability of taking a math class and a physics class is ![0.15](https://tex.z-dn.net/?f=0.15)
How can we find the probability of taking math class or a physics class ?
Given in the question probability of the student taking class
![p(M)=0.70\\p(P)=0.30\\p( M and P)=0.15](https://tex.z-dn.net/?f=p%28M%29%3D0.70%5C%5Cp%28P%29%3D0.30%5C%5Cp%28%20M%20and%20P%29%3D0.15)
So we use the probability union intersection formula
![p(M or P)=p(M)+p(P)-p(M and P)](https://tex.z-dn.net/?f=p%28M%20or%20P%29%3Dp%28M%29%2Bp%28P%29-p%28M%20and%20P%29)
Substitute the values
![p(M or P)=0.7+0.3-0.15\\=0.85](https://tex.z-dn.net/?f=p%28M%20or%20P%29%3D0.7%2B0.3-0.15%5C%5C%3D0.85)
Learn more about probability here :
brainly.com/question/28045837
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<h3>Answer:</h3>
A
Step-by-step explanation:
{-32, 9, 11, 12}
first, find the mean (Find the sum of the data values, and divide the sum by the number of data values )
(-32) + 9 + 11 + 12 = 0
0/0 = 0
then, find the absolute value of the difference between each data value and the mean: |data value – mean|.
-32 - 0= -32
9 -0 = 9
11 -0 = 11
12 -0 = 0
finally, find the sum of the absolute values of the differences. Divide the sum of the absolute values of the differences by the number of data values.
0 - 0 / 4 = 0
answer is 0 (A)
Answer:
I've already answered this question for you.
Step-by-step explanation:
17+r= 19 because you replace r with 2 since r equals too and you get 19
Answer: 2
Step-by-step explanation:
8x4=32, you have to distribute the 8 into the parentheses so you will have 8x2+8x2 which is 16+16=32