The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
Answer:
3x² - 14x + 15
Step-by-step explanation:
Step 1: Write expression
(x - 3)(3x - 5)
Step 2: FOIL
3x² - 5x - 9x + 15
Step 3: Combine like terms
3x² - 14x + 15
Answer:
When x = 2, both expressions have a value of 18
The expressions have equivalent values for any value of x.
The expressions have equivalent values if x = 8.
Step-by-step explanation:
7x+4 3x+5+4x-1
Let x=2
7*2 +4 = 18
3*2+5+4*2-1 = 6+5+8-1=18
When x = 2, both expressions have a value of 18
The expressions are only equivalent for x = 4 and x = 6.
False, they are both equal when x=2
Try x=1
7+4 =11 3+5+4-1 = 11
They are equal with an odd value
When x = 0, the first expression has a value of 4 and the second expression has a value of 5.
4 5-1 =4 false
The expressions are only equivalent when evaluated with even values. false
The expressions should have been evaluated with one odd value and one even value. my best guess is false, if it is true for 2 values it is true for all values
The expressions have equivalent values if x = 8. true
7*8 +4 = 60 3(8)+5 +4(8) -1 =60
The expressions have equivalent values for any value of x.
7x+4 3x+4x +5-1 = 7x+4
They are always equal