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vazorg [7]
3 years ago
6

The answer is wrong please help me

Mathematics
2 answers:
uranmaximum [27]3 years ago
7 0
(- 3 (-2) + 3 = 9)   >  (3(-4) + 9 = -12 + 9 = -3)
max2010maxim [7]3 years ago
4 0
-3*-2=6+3=9 you got that part right
3*-4=-12+9=-3 
therefore 9>-3
You might be interested in
I need help with coming up with equation
Natali5045456 [20]

Let's call a child's ticket c and an adult's ticket a. From this, we can say:

c + a = 116,

since 116 tickets are sold in total.


Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

\$17000 \cdot (1 - \dfrac{1}{4}) = \$12750.


Given these values, we can say:

17000a + 12750c = 1653250,

since each adult ticket a costs 17,000 and each child's ticket c costs 12,750, and these costs sum to 1,653,250.


Now, we have two equations:

17000a + 12750c = 1653250

c + a = 116


Let's solve:

17000a + 12750c = 1653250

a = 116 - c

  • Find a on its own, which will allow us to substitute it into the first equation

17000(116 - c) + 12750a = 1653250

  • Substitute in 116 - c for a

1972000 - 17000c + 12750c = 1653250

  • Apply the Distributive Property

1972000 - 4250c = 1653250

  • Combine like terms

4250c = 318750

  • Subtract 1972000 from both sides of the equation and multiply both sides by -1

c = 75


We have now found that 75 child's tickets were sold. Thus,

75 + a = 116 \Rightarrow a = 116 - 75 = 41,

41 adult tickets were sold as well.


In sum, 41 adult tickets were sold along with 75 child tickets.

6 0
3 years ago
On a particular day, the wind added 4 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 4 miles pe
larisa [96]
Nice so
remember
t=d/s
a(b+c)=ab+ac

time=distance/speed

lets say s=jamie's normal speed
speed agains wind=s-4
speed with wind=s+4

30 miles is agains wind
distance is 54 with wind


t=d/s
t=30/(s-4)
t=54/(s+4)

since they are both equal to t, set them equal to each other

30/(s-4)=54/(s+4)
multipliy both sides by (s+4)(s-4)
30(s+4)=54(s-4)
distribute
30s+120=54s-216
subtract 30s from both sides
120=24s-216
add 216 to both sides
336=24s
divide both sides by 24
14=s


answer is 14 miles per hour without wind
8 0
3 years ago
1. Which number sets does the number
Zina [86]

Answer:

natural numbers and integers

8 0
4 years ago
At what rate percent per annum will rs 1625 amount to rs 2080 in 31/2 years​
melamori03 [73]

Answer:

h does he Debra sorry time to use highlighting due ibyovh free ok jrlgvhvhvwouv see you in John

5 0
4 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
GalinKa [24]

Answer:

Jada should have multiplied both sides of the equation by 108.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:

Step 1: Multiply both sides of the equation by -9/4 as shown:

-4/9 × -9/4 = x/108 × -9/4

-36/-36 = -9x/432

1 = -9x/432

1 = -x/48

Cross multiplying

48 = -x

x = -48

It can also be solved like this:

Given -4/9 = x/108

Multiply both sides by 108 to have:

-4/9 * 108 = x/108 * 108

-4/9 * 108 = 108x/108

-432/9 = x

x = -48

Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.

7 0
3 years ago
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