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Leto [7]
3 years ago
7

If a person rolls a six-sided die and then draws a playing card and checks its color, describe the sample space of possible outc

omes using 1, 2, 3, 4, 5, 6 for the die outcomes and B, R for the card outcomes.
Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

S = {1B, 2B, 3B, 4B, 5B, 6B, 1R, 2R, 3R, 4R, 5R, 6R}

Step-by-step explanation:

The sample space is the set of all possible outcomes in the experiment of rolling a six-sided die and then drawing a playing card and checking its color.

There are 6 possible outcomes for the die roll and two for the color of the card, which yields a total of 12 possible outcomes. The sample space is:

S = {1B, 2B, 3B, 4B, 5B, 6B, 1R, 2R, 3R, 4R, 5R, 6R}

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x=73

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19.5

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F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

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Susan has 4 gallons of juice. How many cups of juice does she have?
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3 years ago
Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which
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Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

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V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L

1.25 liters of oil are needed.

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3 years ago
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