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2 years ago

Which correlation is most likely a causation?

Mathematics

2 answers:

irina1246 [14]2 years ago

6 0

The appropriate response is letter B. The connection is no doubt a causation is the positive relationship between's the quantity of trucks that drive on a street and the measure of support the street needs

I hope the answer will help you.

LekaFEV [45]2 years ago

3 0

Here are the CORRECT answers to the, 6.07 Quiz: Correlation and Causation, quiz.

Please leave a thanks.

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Solve by elimination -7x-20=-14 -2x+10y=-4

sweet-ann [11.9K]

Mark brainliest please mark

6 0

2 years ago

I need a little extra help with number three

diamong [38]

Answer:

The answer to your question is:

Step-by-step explanation:

Data

f(x) = -2x² + 8x - 2

Process

-2x² + 8x = y + 2

-2(x² - 4x + 4) = y + 2 - 8

-2(x - 2)² = y - 6

(x - 2)² = 1/2 (y - 6)

Vertex = (2, 6)

Axis of symmetry = x = 2

y-intercept

f(0) = -2(0)² + 8(0) - 2

f(0) = 0 + 0 - 2

f(0) = -2

Domain (-∞, ∞)

Range (-∞, 6]

See the graph below

6 0

2 years ago

If there are 30 flower bouquets, 4/5 of the bouquets are daises, the rest are tulips. How many bouquets are tulips?

erastova [34]

Answer:

6 bouquets of tulips

Step-by-step explanation:

<h2><u>first find out the number of daisies.. </u></h2>

this is 4/5 * 30

= 24

there are 24 daises...

now to find the number of tulips are:

30 - 24 = 6

there a<u> 6 bouquets of tulips. </u>

4 0

2 years ago

Read 2 more answers

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

8 0

2 years ago

Rewrite the equation by completing the square.

Dennis_Churaev [7]

Once you complete the square, the simplified version of this equation is

(2x - 1)^2= 0

If you want to solve for x, subtract 1 and divide by 2.

x = 0.5

7 0

3 years ago