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SSSSS [86.1K]
3 years ago
11

What is 1/12 (12-v)=1/6(v-6)

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0
 Assuming you want to know the value of "v" 

So, step one we would have solve from the same value 

\frac{1}{12}(12-v) =  \frac{1}{6}(v-6)\\ \frac{1}{12}(12) +  \frac{1}{12} (-v) =  \frac{1}{6}(v)+  \frac{1}{6} (-6)  \\ 1 +  \frac{-1}{12}(v) =  \frac{1}{6}v + -01 \\  \frac{-1}{12} (v) +1  =  \frac{1}{6} - 1

Step two we have to subtract by \frac{1}{6}v on each of your sides (so it can kind of be easier for you to solve) 


So,\frac{1}{6} v  + 1 -  \frac{1}{6}v =  \frac{1}{6}v - 1  \frac{1}{6}v 
You would have to cancel out the right side because it would give you a(n) answer of 1 

Now that we got those steps out of your way, let's subtract 1 to your sides that we're working with 

\frac{-1}{4}(v) +1 -1 \\ = -1 -1

Finally we're close to our answer for v

\frac{-1}{4}(v)= 2

\frac{4}{1} ( \frac{-1}{4} ) cancel this out because it gives you one 

But, keep: \frac{4}{1} (-2) because it gives you the answer

v = 8

Good luck on your assignment
and enjoy your day

~MeIsKaitlyn:)
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SOMEBODY PLEASE HELP ME!!!!!!!​
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50/100

Step-by-step explanation:

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A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
NO LINKS!
lord [1]

Answer:

Part A: 60

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60.

12, 24, 36, 48, 60.

---------------------------------

Part B: 9

81 / 72 = 9

----------------------------------

Part C: 9 (8 + 9)

GCF of 72 and 81 is 9...

Divide 72 by 9 and get 8.

Divide 81 by 9 and get 9.

To check multiply 9 with 8, and multiply 9 by 9.

----------------------------------

Easy! :D (if you don't mind, may I get brainliest please?)

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64-35= 29

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