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SSSSS [86.1K]
3 years ago
11

What is 1/12 (12-v)=1/6(v-6)

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0
 Assuming you want to know the value of "v" 

So, step one we would have solve from the same value 

\frac{1}{12}(12-v) =  \frac{1}{6}(v-6)\\ \frac{1}{12}(12) +  \frac{1}{12} (-v) =  \frac{1}{6}(v)+  \frac{1}{6} (-6)  \\ 1 +  \frac{-1}{12}(v) =  \frac{1}{6}v + -01 \\  \frac{-1}{12} (v) +1  =  \frac{1}{6} - 1

Step two we have to subtract by \frac{1}{6}v on each of your sides (so it can kind of be easier for you to solve) 


So,\frac{1}{6} v  + 1 -  \frac{1}{6}v =  \frac{1}{6}v - 1  \frac{1}{6}v 
You would have to cancel out the right side because it would give you a(n) answer of 1 

Now that we got those steps out of your way, let's subtract 1 to your sides that we're working with 

\frac{-1}{4}(v) +1 -1 \\ = -1 -1

Finally we're close to our answer for v

\frac{-1}{4}(v)= 2

\frac{4}{1} ( \frac{-1}{4} ) cancel this out because it gives you one 

But, keep: \frac{4}{1} (-2) because it gives you the answer

v = 8

Good luck on your assignment
and enjoy your day

~MeIsKaitlyn:)
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Complete Question

Express the confidence interval 0.555 less than p less than  0.777 in the form Modifying above p with caret plus or minus Upper E.

Answer:

The modified representation is \r p \pm  E  = 0.666 \pm  0.111

Step-by-step explanation:

From the question we are told that

    The  confidence interval interval is  0.555 <  p <  0.777

Now looking at the values that make up  the up confidence interval we see that this is a symmetric  confidence interval(This because the interval covers 95%  of the area under the normal curve which mean that the probability of a value falling outside the interval is 0.05 which is divided into two , the first half on the left -tail and the second half on the right tail  as shown on the figure in the first uploaded image(reference - Yale University ) ) which means

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Generally the margin of error is mathematically represented as

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Where  K is the length of the confidence interval which iis mathematically represented as

           K  =  0.777 -0.555

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Hence  

          ME  =  \frac{1}{2}  *  0.222

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So the confidence interval can now be represented as

        \r p \pm  E  = 0.666 \pm  0.111

     

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Step-by-step explanation:

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