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SSSSS [86.1K]
2 years ago
11

What is 1/12 (12-v)=1/6(v-6)

Mathematics
1 answer:
8_murik_8 [283]2 years ago
5 0
 Assuming you want to know the value of "v" 

So, step one we would have solve from the same value 

\frac{1}{12}(12-v) =  \frac{1}{6}(v-6)\\ \frac{1}{12}(12) +  \frac{1}{12} (-v) =  \frac{1}{6}(v)+  \frac{1}{6} (-6)  \\ 1 +  \frac{-1}{12}(v) =  \frac{1}{6}v + -01 \\  \frac{-1}{12} (v) +1  =  \frac{1}{6} - 1

Step two we have to subtract by \frac{1}{6}v on each of your sides (so it can kind of be easier for you to solve) 


So,\frac{1}{6} v  + 1 -  \frac{1}{6}v =  \frac{1}{6}v - 1  \frac{1}{6}v 
You would have to cancel out the right side because it would give you a(n) answer of 1 

Now that we got those steps out of your way, let's subtract 1 to your sides that we're working with 

\frac{-1}{4}(v) +1 -1 \\ = -1 -1

Finally we're close to our answer for v

\frac{-1}{4}(v)= 2

\frac{4}{1} ( \frac{-1}{4} ) cancel this out because it gives you one 

But, keep: \frac{4}{1} (-2) because it gives you the answer

v = 8

Good luck on your assignment
and enjoy your day

~MeIsKaitlyn:)
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Use the formula v=5to the third power where v is the volume and s is the edge length of the cube to solve this problem what is t
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V = 25*5 That's 2 fives multiplied together.
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3 years ago
You invested $1,200 in a mutual fund. Your account now has a value of $1,333. what was your gain?
OleMash [197]
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7 0
3 years ago
Read 2 more answers
ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
2 years ago
I'LL WON'T BE OFFEND IF U DON'T HELP ME WITH THIS
Evgesh-ka [11]

The average is found by adding the numbers and dividing by 2.

Since the average is 17, the total of the two numbers must equal 17 x 2 = 34.


One number is given as 11, so subtract 11 from 34:

34 - 11 = 23

The other number is 23.

Too check: add 11 and 23 and then divide by 2:

11 + 23 = 34

34/2 = 17.

5 0
3 years ago
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