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4 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

Mathematics

1 answer:

never [62]4 years ago

3 0

Answer:

Step-by-step explanation:

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The sum of three consecutive even numbers is 162.What is the smallest of the three numbers?

kap26 [50]

The smallest number is 53

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3 years ago

Which equation represents a line parallel to the x-axis

Andru [333]

Paralell lines have same slope

paralell to x axis means slope of x axis=slope of line
slopt of x axis=rise/run, rise=0, run=infinity, so slope=0

y=mx+b
m=slope
if m=0,
y=0x+b
y=b

therefor the answer is an equation that is y=constant where there is no x

answer is 2) y=10

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3 years ago

Is this correct? Thanks.

ohaa [14]

Answer:

yes it is

Step-by-step explanation:

hope it will help you if yes so make brainlist

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3 years ago

(b) An advertising agency finds that, of its 170 clients, 115 use Television, 110 use Radio and 130 use Magazines. Also 85 use T

Alex73 [517]

Answer:

Here you go with your correct answer

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2 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

3 years ago