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3 years ago

(Picture Included) could someone give me the answers to #6?

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

1/6 I think i might be wrong

klasskru [66]3 years ago

4 0

If it’s out of 12 then the probability is 1 because there’s only 1 side that says 4

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Write 3 3/4 as an improper fraction?

ale4655 [162]

Answer:

15/4

Step-by-step explanation:

multiply the whole number (3) by the denominator (4), then add the numerator (3) then put that over the denominator to convert any mixed number into an improper fraction.

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2 years ago

Read 2 more answers

Select the correct answer.

Alla [95]

Answer:

Step-by-step explanation:

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3 years ago

Which of the following constructions were never accomplished by the Greeks

Ilia_Sergeevich [38]

Answer:

B- doubling a cube

D- trisecting any angle

Step-by-step explanation:

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3 years ago

Thomas has 21 singles, 30 triples, and 13 homeruns. What is his SLG so far if he has 198 at bats?

Sedaia [141]

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3 years ago

The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

3 0

3 years ago