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Margarita [4]
3 years ago
12

What to the power of 4 equles 625

Mathematics
1 answer:
jeyben [28]3 years ago
4 0

Answer:

5^4

Step-by-step explanation:

5x5x5x5=625

5 raised to the power of 4

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The hypotenuse of a right triangle is 13.0, and one leg is 9.0 units shorter than the other. Find the dimensions of the figure (
Darina [25.2K]
Let, one leg be x units. 
since the other leg is 9.0 units shorter than the other, 
the measure of the other leg =x-9 
hypotenuse =13.0 units 
According to Pythagorean theorem, the square of the hypotenuse is equal to the sum of squares of the other two sides.  
x^2 +(x-9)^2 =13^2 
x^2 + x^2 -18x +81 = 169 
2x^2-18x-88=0 
Divide the whole equation by 2 
x^2 - 9x -44 =0  
Let's use the quadratic formula to find the roots. 
formula: x= [-b ± sqrt(b^2-4*a*c)]/2*a  
a=1 b=-9 c=-44 
x= [9±sqrt(81+176)]/2
 =[9±sqrt(257)]/2
 =[9±16.03]/2
 =25.03/2 or -7.03/2
 length of a triangle cannot be negative,
 Therefore, x=25.03/2 =12.52 
 one leg =12.5 units
 other leg =12.52-9 =3.5 units
4 0
3 years ago
Which equation best represents the line of best fit for the scatterplot?
Elena L [17]

Answer:

The answer for this problem is

C) y = -x + 6

Step-by-step explanation:

I know this because I just did the test

5 0
3 years ago
What is the interquartile range of the data set?
AveGali [126]
There is no data provided but if your asking what an interquartile range is ?? It’s a measure of variability based on dividing a data set into quartile a
6 0
3 years ago
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
Joshua spends 25 minutes of each day reading.Let d be the number of days that he reads and let m represent the total minutes of
snow_tiger [21]
The independent variable is the days he spends reading because nothing we have can determine that. However the dependent variable is the total minutes of reading because it relies on the independent variable to figure out. You can't find the total minutes without knowing the days he spends. The equation sould be d times the amount he reads per day =m
4 0
3 years ago
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