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Delicious77 [7]
3 years ago
14

What is the simplified expression for 3 a squared + 9 a b + 5 minus 4 a squared minus 4 a b + 3?

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

-1ab^2 + 5b + 8

Step-by-step explanation:

3a^2+9ab+5-4a^2-4ab+3

3a^2-4ab^2=-1ab^2

9ab-4ab=5ab

5+3=8

-1ab^2+5ab+8

attashe74 [19]3 years ago
6 0

Answer:

Step-by-step explanation:

3a²+9ab+5-(4a²-4ab+3)=3a²+9ab+5-4a²+4ab-3=-a²+13ab+2

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f^-1(v)=v/x-3/x

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How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
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8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

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Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

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<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

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<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

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Answer:

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<h2>HOPE THIS HELP YOU!!! ;))))</h2>

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