All categories

2 years ago

10. George earns $455 per week. He receives a 20% raise. What is George's new weekly salary?

Mathematics

2 answers:

djverab [1.8K]2 years ago

8 0

Answer:

$546

Step-by-step explanation:

455*.20=91

91+455+546

KIM [24]2 years ago

7 0

If you find what 20% of 455 is (91) and then add it you’ll get your answer 546

You might be interested in

Complete the input-output table: x 3x + 7 0 4 8 14

salantis [7]

Step-by-step explanation:

When x = 0,

3x + 7

= 3 ( 0 ) + 7

= 0 + 7

= 7

When x = 4,

3x + 7

= 3 ( 4 ) + 7

= 12 + 7

= 19

When x = 8,

3x + 7

= 3 ( 8 ) + 7

= 24 + 7

= 31

When x = 14,

3x + 14

= 3 ( 14 ) + 14

= 14 ( 3 + 1 )

= 14 ( 4 )

= 56

3 0

2 years ago

Any help with this greatly appreciated.

Anestetic [448]

Put the equation in standard linear form.

$x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}$

Find the integrating factor.

$\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5$

Multiply both sides by $\mu$ .

$(t+5) x'(t) + x(t) = 5(t+5)e^{5t}$

Now the left side the derivative of a product,

$\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}$

Integrate both sides.

$(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt$

On the right side, integrate by parts.

$(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C$

Solve for $x(t)$ .

$\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}$

3 0

1 year ago

What is the of 80,000×200

Eddi Din [679]

The answer for 80,000 * 200 is 16,000,000

4 0

3 years ago

What is -4/5 + 3/20 in simplest form

Helga [31]

-4/5 = -16/20, so the new expression is (-16/20)+(3/20)
then, -16 + 3 is -13, so the solution is -13/20

6 0

3 years ago

Read 2 more answers

A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo

Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) $10X+5X+5X=300 => 20X = 300 => X = 15$ days for the lessons

b) $5X+10X+8X = 300 => 23X = 300 => X = 13.04$ days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) $10X+5X=300 => 15X = 300 => X = 20$ days for the lessons

b) $5X+10X = 300 => 15X = 300 => X = 20$ days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) $10(10/24)+5X+5X= 300 => X = 29.58$ days for the lessons

b) $5(10/24)+10X+8X = 300 => X = 16.51$ days for the tests

so at the end to complete both tasks they need 29.58 days

4 0

2 years ago