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Whitepunk [10]
3 years ago
9

value of a machine depreciates by 20% every year. if present value is 160000 find its value last year.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0
192,000.

Just multiply 160,000 by 0.2 to get 32,000, then add that to the original value to get 192,000.
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A. What is the slope of the line passing through the points (2,3) and (2,-3)?
OlgaM077 [116]

Answer:

The slope is the change in Y over the change in X:

Slope = (-3 - 3) / (2 -2) = 0/0

Since the slope contains a division of 0, it is undefined, therefore the answer would be neither.

3 0
4 years ago
Juan is working two summer jobs, making $12 per hour babysitting and making $16 per hour lifeguarding. In a given week, he can w
Semenov [28]

\text{Let }b=

Let b=

\,\,\text{the number of hours babysitting}

the number of hours babysitting

\text{Let }l=

Let l=

\,\,\text{the number of hours lifeguarding}

the number of hours lifeguarding

\text{\textquotedblleft at most 17 hours"}\rightarrow \text{17 or fewer hours}

“at most 17 hours"→17 or fewer hours

Use a \le≤ symbol

Therefore the total number of hours worked in both jobs, b+lb+l, must be less than or equal to 17:17:

b+l\le 17

b+l≤17

\text{\textquotedblleft at least \$240"}\rightarrow \text{\$240 or more}

“at least $240"→$240 or more

Use a \ge≥ symbol

Juan makes $12 per hour babysitting, so in bb hours he will make 12b12b dollars. Juan makes $16 per hour lifeguarding, so in ll hours he will make 16l16l dollars. The total amount earned 12b+16l12b+16l must be greater than or equal to \$240:$240:

12b+16l\ge 240

12b+16l≥240

\text{Plug in }\color{green}{3}\text{ for }b\text{ and solve each inequality:}

Plug in 3 for b and solve each inequality:

Juan worked 3 hours babysitting

\begin{aligned}b+l\le 17\hspace{10px}\text{and}\hspace{10px}&12b+16l\ge 240 \\ \color{green}{3}+l\le 17\hspace{10px}\text{and}\hspace{10px}&12\left(\color{green}{3}\right)+16l\ge 240 \\ l\le 14\hspace{10px}\text{and}\hspace{10px}&36+16l\ge 240 \\ \hspace{10px}&16l\ge 204 \\ \hspace{10px}&l\ge 12.75 \\ \end{aligned}

b+l≤17and

3+l≤17and

l≤14and

​  

 

12b+16l≥240

12(3)+16l≥240

36+16l≥240

16l≥204

l≥12.75

​  

 

\text{The values of }l\text{ that make BOTH inequalities true are:}

The values of l that make BOTH inequalities true are:

\{13,\ 14\}

{13, 14}

\text{(the final answer is this entire list)}

(the final answer is this entire list)

6 0
3 years ago
Change 95.61º to degrees, minutes, and seconds.
nexus9112 [7]

Answer:

Claire loaded her truck with vegetables from her garden to sell at a local market. Which of the following BEST describes Claire's truck? *

Step-by-step explanation:

Claire loaded her truck with vegetables from her garden to sell at a local market. Which of the following BEST describes Claire's truck? *

7 0
3 years ago
Points R, T, S, and Q are
Sladkaya [172]
Neither collinear nor coplanar.
All of the points would have to be on the same line to make them collinear, and they would also have to be on the same plane to make them coplanar. We can see in the diagram that not all of the points are on a line, and that some are at different heights than others.
6 0
3 years ago
There is a total of 2,512 people attending the fun fair. 5/8 of sttemdees are students and 1/4 of attendees are parents. the res
kvv77 [185]

Answer:

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of people attending the fun fair = 2,512

Fraction of people attending the fun fair that are students = 5/8

Fraction of people attending the fun fair that are parents = 1/4

Rest of the people attending the fun fair lives in the neighborhood

2. Let's calculate the number of students, parents and people living in the neighborhood

Students:

Fraction of people attending the fun fair that are students = 5/8

5/8 * 2,512 = 1,570

1,570 of the people attending the fun fair are students

Parents:

Fraction of people attending the fun fair that are parents = 1/4

1/4 * 2,512 = 628

628 of the people attending the fun fair are parents

People living in the neighborhood

2,512 - 1,570 - 628 = 314

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

8 0
3 years ago
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