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Inga [223]
3 years ago
14

How do untouchables find the diameter of a area

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer:

Step-by-step explanation:

To find the area with the diameter, simply divide the diameter by 2, plug it into the radius formula, and solve as before. To get the area from the circumference, take the square of the circumference and divide by pi.

<em>hope this helps~</em>

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A student studying his classmates' cars' ages reports the 5-number summary as {1, 3, 4, 8, 20}. what is the iqr for his data?
timurjin [86]

IQR for the data {1, 3, 4, 8, 20} is 5.

Interquartile Range(IQR) for a data is defined as the difference between third quartile and first quartile.

denoted by  IQR=Q₃-Q₁              (Q₃ is third quartile and Q₁ is first quartile)

The five number summary of a data set is represented as

{minimum, first quartile , second quartile , third quartile , maximum}..…(1)

According to the question

{1, 3, 4, 8, 20}

On comparing it with equation   …(1)

minimum=1

Q₁ =3    , Q₂=4 , Q₃=8 , maximum =20

IQR=Q₃-Q₁

Substituting the values we get

IQR=8-3=5.

Therefore , Interquartile Range for the data {1, 3, 4, 8, 20} is 5.

Learn more about Inter Quartile Range here brainly.com/question/28037049

#SPJ4

3 0
1 year ago
What is the area of the triangle given below?
daser333 [38]

Answer:

c brainliest please

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The temperature in Toronto was 14 F. The temperature that same night fell to -5 F. What was the difference in temperatures?
Alex Ar [27]

Answer:

a 9 degrees

Step-by-step explanation:

so I'm not sure but if this is the right answer I think it's 9 so basically you do 14-5=9

6 0
3 years ago
Which ratio forms a proportion with 16/20 ?
zvonat [6]
D. 4/5 since
16 \div 4 = 4
20 \div 4 = 5
same as 4/5
8 0
3 years ago
Read 2 more answers
Which expression is equivalent to 3√50 × √22 ?
8_murik_8 [283]

\longrightarrow{\green{C.\:30 \sqrt{11} }} ✔

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

3 \sqrt{50}  \times  \sqrt{22}  \\ \\ = 3 \sqrt{50 \times 22}  \\ \\ = 3 \sqrt{1100}  \\ \\ = 3 \sqrt{2 \times 2 \times 5 \times 5 \times 11}  \\ \\ = 3 \sqrt{ {2}^{2}  \times  {5}^{2}  \times 11}  \\ \\ = 3 \times 2 \times 5 \sqrt{11}  \\\\  = 30 \sqrt{11}

\bold{ \green{ \star{ \orange{Mystique35}}}}⋆

5 0
3 years ago
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