Answer:
<h3>

</h3>
Step-by-step explanation:
Given,
diameter ( d ) = 12 in
height ( h ) = 15 in
<u>finding </u><u>the </u><u>radius </u><u>of </u><u>a </u><u>cylinder</u>
Radius is just half of diameter.
Radius ( r ) = 12 / 2 = 6 in
<u>finding </u><u>the </u><u>volume </u><u>of </u><u>a </u><u>cylinder </u><u>having </u><u>radius </u><u>of </u><u>6</u><u> </u><u>in </u><u>and </u><u>height </u><u>of </u><u>1</u><u>5</u><u> </u><u>in</u>
Volume of a cylinder = <u>
</u>
⇒
⇒
⇒<u>
</u>
Hope I helped!
Best regards!!
5 - 1 = 4 = 2^2
14 - 5 = 9 = 3^2
30 - 14 = 16 = 4^2
55 - 30 = 25 = 5^2
Start with 1, then add 2^2, 3^3, 4^2, 5^2, 6^2, etc.
Answer:
(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010
(b)
(1 – p) = 0.010
(c)
E(x) = 25000 x 0.010
= 259.2
Explanation has given below.
Step-by-step explanation:
Solution:
(a) Probability that a triplet is decoded.
2 out of three
P = 0.94, n = 3
m= no of correct bits
m bit (3, 0.94)
At p(m≤1) = B (1; 3, 0.94)
= 0.010
(b) Using your answer to part (a),
(1 – p) = 0.010
Error for 1 bit transmission error.
(c) How does your answer to part (a) change if each bit is repeated five times (instead of three?
P( m ≤ 2 )
L = Bit (5, 0.94)
= B (2; 5, 0.94)
= 0.002
(d) Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?
Given:
h = 25000
Bits are switched during transmission between two computers = 6% = 0.06
m = Bit (25000, 0.06)
E(m) = np
= 25000 x 0.06
= 1500
m = Bit (25000, 0.01)
E(m) = 25000 x 0.010
= 259.2
Answer:
-0.2
Step-by-step explanation:
Sine and cosine are co-functions.
That means, cos(90-x)=sin(x) or sin(90-x)=cos(x).
So here since cos(90-x)=-0.2, then sin(x)=-0.2.
Answer:
Therefore there's a 99.99% probability the motherboard of your new computer will last for at least 15 years.
Step-by-step explanation:
This is the general idea to solve the problem.
Suppose that the mean and variance of the your distribution are .
respectively. Then, according to the problem you are looking for the probability.

Consider then the following random variable.

Using the central limit theorem
distribution will be close to normal, and its mean and variance will be
, respectively. Therefore you just have to find the probability that a normally distributed random variable with that mean and that variance which I just mentioned is less than 14.
For this case we have that

Then you have that

and we have that if
is a normally distributed random variables with mean 280 and variance 70 we have that

the actual probability we are looking for is

Therefore there's a 99.99% probability the motherboard of your new computer will last for at least 15 years.