Answer:
A translation by 1 units to the right and 3 units down.
Step-by-step explanation:
Given the information from the study, the average soil saturation for the county last year is 1.2 times the saturation reported for the Northwest part of the county this year.
<span>Also, the average soil saturation for the county last year is 0.25 of the saturation reported for the Southeast part of the county this year.</span>
Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Answer:
$3.583
Step-by-step explanation:
Given the monthly stock prices :
January = $3.50
February = $2.25
March = $5.00
The average monthly change in price of XYZ stock from. JANUARY through MARCH is;
(January + February + March) / 3
Average monthly change :
(3.50 + 2.25 + 5.00) / 3
$10.75 / 3
= $3.583
3/7. if you make them equivalent fractions it would be 30/70 or 14/70. 30/70 is bigger.