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Ket [755]
3 years ago
10

A = a+b+c/3 Solve for b this is a literal equation problem please show steps

Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

b=3A-a-c

Step-by-step explanation:

$A=\frac{a+b+c}{3} $

Multiply both sides by 3

$3A=a+b+c $

Add -b-c both sides

3A-a-c=b

b=3A-a-c

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________is an acute angle and sin theta and cos theta are given. Use identities to find tangent theta, cosecant theta, secant th
AnnyKZ [126]

Answer:

tangent theta = 12/5,

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Step-by-step explanation:

Given sine theta= 12/13, cosine theta= 5/13.

According to SOH CAH TOA

Sintheta = Opposite/Hypotenuse = 12/13

Cosine theta = Adjacent/Hypotenuse = 5/13

Opposite = 12, Adjacent = 5, Hypotenuse = 13

Tan theta = Opposite/Adjacent = 12/5.

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cosecant theta = 13/12

secant theta = 1/cos theta = 1/{5/13}

Secant theta = 13/5.

Cotangent theta = 1/tan theta = 1/{12/5} = 5/12

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4 years ago
9.3x10^7 to regular notation
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Answer:

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Help me below pleasse
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