Given 2.50x + 3.50y < 30.
Where x represent the number of hamburgers and y represent the number of cheeseburgers.
Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.
So, first step is to plug in y=4 in the given inequality. So,
2.50x+3.50(4)<30
2.50x+14 <30
2.50x<30- 14 Subtracting 14 from each sides.
2.50x< 16
Dividing each sides by 2.50.
x<6.4
Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,
thus x = 6 hamburgers
So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15
Hope this helps!!
The slop would be 1/6.
you put it into slope intercept form (y=mx+b). parallel lines always have the same slope.
Here, we have to examine the equation of the straight line which is denoted by: y = m x +c where "m" is the slope which represents the steepness and c is the y-intercept
Here, the two linear functions have the same slope "m" and the same y-intercept "c". When both these are the same, the two linear functions are representing the same straight line.
Therefore, Jeremy is correct in his argument.
(2/3)*(c-18)=7 <em>(Multiply terms on both sides of equation by 3)</em>
2(c-18)=21
2c-36=21
2c=57
c=57/2
c=28.5
