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adelina 88 [10]
4 years ago
9

Suppose that a sample of 10 observations has a standard deviation of 3, then the sum of the squared deviations from the sample m

ean is 30.
TRUE or FALSE?
Mathematics
1 answer:
kvasek [131]4 years ago
3 0

Answer:

False

Step-by-step explanation:

Standard deviation (SD) = 3

Sample size (n) = 10

The standard deviation of a sample is determined as the square root of the sum of the squared deviations from the sample mean (S) divided by number of degrees of freedom (n-1). The sum of the squared deviations is:

SD= \sqrt{\frac{S} {n-1}}\\ 3= \sqrt{\frac{S} {10-1}}\\S=9*9 = 81

The sum of the squared deviations from the sample mean is 81. Therefore, the statement is false.

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The first ten terms of the sequence a_n=1 + (-\frac{4}{9} )^n is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\

When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\

The first ten terms of the sequence a_n=1 + (-\frac{4}{9} )^n is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Select three numbers that are between -0.55 and -0.54.
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