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Alexeev081 [22]
4 years ago
7

There are 12 players on a new softball team. Before the team starts playing games, the team must pay a total registration fee on

$572. Along with the registration fee, the team will also spend a total of 1240 on equipment.
To pay for the registration fee and the equipment, the players held a car wash and raised $786. They then decided to sell candles for $9.50 per candle to cover the remaining cost. If each player sells the same number of candles, how many candles must each player sell?
Mathematics
2 answers:
stepan [7]4 years ago
5 0
Make the question easier to understand
Amiraneli [1.4K]4 years ago
4 0
The softball team would have to sell 128 candles, hope this help.
@FauxGeoDuck
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motikmotik
Get rid of all common factors.
36/4 = 9
x^9/x^7 = x^2
y^4/y^3 = y

\boxed{\frac{36x^9y^4}{4x^7y^3}=9x^2y}
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How many servings of<br> cups are in 33 cups of ice cream?
Galina-37 [17]

Answer:

I am 99% sure its 33 servings

Step-by-step explanation:

because the question says that "how many servings of <u>cups</u> are in <u>33 cups</u>".

(hopefully im right) and HOPEFULLY THIS HELPS. : )

5 0
4 years ago
3x+8y=15 , 2x−8y=10
faltersainse [42]
I think is should be (5,0)
3 0
3 years ago
Read 2 more answers
Factorize x^4 + 2x^3 - 11x^2 - 12x + 36 <br><br>I need the steps.<br>Please i need this for today.
Yuliya22 [10]

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6 0
2 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p: n = 195,
Troyanec [42]

Answer:

c. 0.778 < p < 0.883.

Step-by-step explanation:

The formula for confidence interval for proportion =

p ± z score × √p(1 - p)/n

p = x/n

n = 195, x = 162

z score for 95% confidence Interval = 1.96

p = 162/195

p = 0.8307692308

p ≈ approximately equal to = 0.8308

0.8308 ± 1.96 × √0.8308 × (1 - 0.8308)/195

0.8308 ± 1.96 ×√0.8308 × 0.1692/195

0.8308 ± 1.96 × √0.0007208788

0.8308 ± 1.96 × 0.0268491862

0.8308 ± 0.052624405

Confidence Interval

= 0.8308 - 0.052624405

= 0.778175595

Approximately = 0.778

= 0.8308 + 0.052624405

= 0.883424405

Approximately = p

0.883

Therefore, the confidence interval for this proportion = (0.778, 0.883) or option c. 0.778 < p < 0.883

6 0
3 years ago
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