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3 years ago

The airport has a moving walkway that moves at 2 feet per second. Suppose Calvin can travel 152

Mathematics

1 answer:

Rudiy273 years ago

5 0

Answer:

0.94 ft/sec

Step-by-step explanation:

Airport: 2 feet per second.

Total distance 152 ft in the same amount of time it takes him to talk 72 feet on the pavement.

152/2 = 76 - This is how many seconds he was walking in the airport.

He walked 76 seconds and moved 152 feet.

So that means if the SAME time was used so 76 seconds he walked 72 feet, then we can do 72ft/76sec to get 0.94ft/sec

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1. Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2). Graph BGTS and its image after a translation

larisa86 [58]

The image is attached with answer

<h3>What is a Quadrilateral ?</h3>

A quadrilateral is a polygon with four sides , four angles and four vertices.

It is given in the question that

Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2).

A graph has to be drawn of

its image after a translation along (5,0) and a reflection in the x-axis.

The coordinates after translation and reflection is is B (8, -4), G (6, -3), T (6, -1), and S (7, -2).

The image is attached with the answer .

To know more about Quadrilateral

brainly.com/question/13805601

#SPJ1

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2 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago

Hernando's salary was $54,500 last year. This year his salary was cut to $52,355. Find the percent decrease. Round to the neares

Otrada [13]

Answer:

Decrease by 3.9%

Step-by-step explanation:

54,500(1-x) = 52355

x=0.03935... = 3.935% or 3.9%

8 0

2 years ago

Read 2 more answers

4. Z BAD is bisected by AC. What is the value of x? (3pts)

Snowcat [4.5K]

(-4x + 42) = (64 - 6x)
-4x + 42 = 64 - 6x
+6x on both sides
2x + 42 = 64
-42 on both sides
2x = 22
/2 on both sides
x = 11

Answer:
x = 11

4 0

3 years ago

The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V

aleksklad [387]

Answer:

The answer is explained below

Step-by-step explanation:

Given that The volume of air inside a rubber ball with radius r can be found using the function V(r) = $\frac{4}{3}\pi r^3$ , this means that the volume of the air inside the rubber ball is a function of the radius of the rubber ball, that is as the radius of the rubber ball changes, also the volume of the ball changes.

As seen from the function, the radius is directly proportional to the volume of the ball, if the radius increases, the volume also increases.

$V(\frac{5}{7} )$ is equal to the volume of the ball when the radius of the ball is $\frac{5}{7}$ . Therefore:

$V(\frac{5}{7} )=\frac{4}{3} \pi *(\frac{5}{7} )^3=1.53\ unit^3$

3 0

3 years ago