Answer:
This is truly false.
When determining which x-values would make an expression undefined, you do need to include the factors you canceled out.
Step-by-step explanation:
When working with functions, it is said to be undefined when the value of the function doesn't take on a value, and this occurs when the denominator is equal to 0.
Take for example
(x-2)/(x-2)
This simple function can be simplifted further by cancelling out the factors to get 1, but that doesn't change the fact that, at x=1, this function becomes undefined.
Because, the values of x can vary and can take on values that can make the denominator to be 0, factors that are cancelled need to be included in checking for where a function is undefined.
Hope this Helps!!!!
