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Dafna1 [17]
3 years ago
8

Divide: 8.6) 3.440 short answer

Mathematics
2 answers:
ivanzaharov [21]3 years ago
5 0

Answer:

well your answer will be 2.5

Step-by-step explanation:

2.5

AnnZ [28]3 years ago
3 0

Answer:

(86/25)

Step-by-step explanation:

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Just a tad bit more points :)
swat32

Answer:

Thx have a great day :)

Step-by-step explanation:

7 0
3 years ago
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What is the circumference of circle with a diameter of 9 feet? Use 3.14 for tt
ankoles [38]

Answer:

28.26

Step-by-step explanation:

The formula for calculating diameter is π<em>d</em> (pi times the diameter), so 3.14 times 9 is 28.26.

4 0
3 years ago
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A line segment of length k is divided into 3 equal parts what is the distance between midpoints of the first and third segments
anastassius [24]

Line segment of length k is divided into 3 equal parts.

so first segment is 0-k/3 and third segment is 2/3k-k

so mid-pt of 1st = k/6 and 3rd = 5/6k

so the distance in between = 5/6k-k/6 = 4/6k = 2/3k

4 0
3 years ago
Solve: 2x-3 = 5(x + 6)
Slav-nsk [51]

Answer:

2x - 3 = 5(x + 6)

2x - 3 = 5x + 30

-33 = 3x

x = -11

7 0
2 years ago
Read 2 more answers
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
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