All categories

3 years ago

What is he least common multiple of 5 and 6

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Answer:

30.

Step-by-step explanation:

6 = 2 * 3

5 = 5

LCM = 2 * 3 * 5 = 30.

You might be interested in

Help with Algebra with Trinominals and Vertex Form. WILL MARK BRAINLIEST

slega [8]

Answer:

(b/2)^2

Step-by-step explanation:

7 0

3 years ago

Simplify the expression <br><br> 12x^-6y^10X3x^7y

harkovskaia [24]

Answer:

12xy₁₁x₃

Step-by-step explanation:

4 0

3 years ago

Can someone help me with this math homework please!

andrew11 [14]

Answer:

I'm pretty sure it is 0.75

Step-by-step explanation:

It is a3 so that means it is the 3rd answer in the sequence.

6 0

3 years ago

Read 2 more answers

1. Using the above

Ivan

Answer:

yes there is a correlation

Step-by-step explanation:

here's how I found this by looking up all key words.

4 0

2 years ago

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

5 0

3 years ago