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Salsk061 [2.6K]
2 years ago
15

How many zero pairs must be added to the function x^2-10x-4 in order to begin writing the function in vertex for

Mathematics
1 answer:
Natalija [7]2 years ago
5 0
The answer is:

(x-5 - sq root 29) (x-5 + sq root 29)
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HELP ME PLEASE FOR BRAINLESTT!!
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The solution of a system of linear equations is:

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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

Therefore, the length of radius of the given circle is 2.

3 0
3 years ago
The bases of the trapezoid are 6 and 10. The height is 4. Find the area.
kari74 [83]
<h2>Answer:</h2>

b. \ \boxed{32 \sq. \ units}

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, b_{1}\,and\,b_{2}. Also, the height H of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of b_{1},b_{2}\:and\:H is:

A=\frac{(b_{1}\text{+}b_{2})h}{2}

Since:

b_{1}=6, \ b_{2}=10, \ and \ H=4

The area is:

A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}

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3 years ago
Select the correct answer.
charle [14.2K]

Answer: C

Step-by-step explanation:

4^{-11/3 -(-2/3)=4^{-11/3 + 2/3}=4^{-3}=1/64

5 0
2 years ago
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