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Salsk061 [2.6K]
3 years ago
15

How many zero pairs must be added to the function x^2-10x-4 in order to begin writing the function in vertex for

Mathematics
1 answer:
Natalija [7]3 years ago
5 0
The answer is:

(x-5 - sq root 29) (x-5 + sq root 29)
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Na função y = x² - 2x +1, temos que a = 1, b = -2 e c = 1, calcule as coordenadas do vértice da parábola​
MrRissso [65]

Answer:

(1, 0)

Step-by-step explanation:

x = -b / 2a

x = 2 / 2(1)

x = 2 / 2

x = 1

y = x^2 - 2x + 1

y = (1)^2 - 2(1) + 1

y = 1 - 2 + 1

y = -1 + 1

y = 0

vértice: (1, 0)

4 0
3 years ago
What is the equation of a line perpendicular to y=2.5x+5
Sauron [17]

Answer:

y = -0.4 + c

Step-by-step explanation:

y = mx + c (original form)

m ⊥ - 1/m

2.5 = 25/10

25/10 ⊥ -10/25

-10/25 = -0.4

y = -0.4x + c

     

3 0
2 years ago
What is another way to write 17 tens 6 ones​
Alisiya [41]

Answer:

176

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the measure exterior angle of a regular octagon
Nady [450]
The formula for the number of degrees of an external polygon is
360/n where n is the number of sides

octogon has 8 sides
360/8=45
answer is 45 degrees
4 0
3 years ago
Can someone show me how to do this ?
Savatey [412]
The point slope formula is y - y1 = m(x - x1)

the value x1 is the x coordinate of a point
the value y1 is the y coordinate of a point
the value m is the slope, which is 3

therefore, x1 = -2 & y1 = 1

Then, all you do is plug in the points:

y - 1 = 3(x + 2)

NOTE:
It is 3(x + 2) instead of 3(x - 2) because the formula is (x - x1). If you plug x1 in, it is (x - (-2)). 2 negatives cancel out to be a positive, so it is (x + 2)

7 0
3 years ago
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