Calculate the volume pyramid whose height de Priangular by of a 20cm, and has base of 8cm by 12cm by 150mm

Tju [1.3M]

The answer would be....(r + 3w) × ( r - 3t)

6 0

3 years ago

A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an

lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of $v_2=613.87m/sec$

Step-by-step explanation:

We have given internal diameter of the garden hose $d_1=0.740in=1.8796cm$

So radius $r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm$

So area $A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2$

Water in the hose has a speed of 4 ft/sec

So $v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)$

Number of holes n = 36

Diameter of each hole $d_2=0.1397cm$

So radius $r_2=0.0698cm$

So area $A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2$

From continuity equation

$A_1v_1=nA_2v_2$

$2.7733\times 121.92=36\times 0.0153\times v_2$

$v_2=613.87m/sec$

7 0

3 years ago

Please please help me

Gekata [30.6K]

Answer:

$\large\boxed{\dfrac{\boxed{8}}{81}}$

Step-by-step explanation:

$\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}$

$\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}$

8 0

3 years ago

Can someone please explain to me how to get this answer?

SIZIF [17.4K]

Answers:
A = 120
b = 45.0
c = 33.2

Side Note: only one triangle is possible
See attached for a visual. I used GeoGebra to draw the triangle.

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Explanation:

We are given the following information
B = 35
C = 25
a = 68

We need to find the following
A, b, c

where the lower case letters represent the side lengths; the upper case letters are the angles. The angles are opposite their corresponding sides. For instance, side lowercase b is opposite angle uppercase B. The other letters are positioned the same way.

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First use the idea that for any triangle, the three angles (A,B,C) must add to 180 degrees
A+B+C = 180
Replace B and C with 35 and 25. Solve for angle A
A+35+25 = 180
A+60 = 180
A+60-60 = 180-60
A = 120

Now that we know the three angles A = 120, B = 35, C = 25, we can find the missing sides 'b' and 'c'

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We will use the law of sines to find side b
sin(A)/a = sin(B)/b
sin(120)/68 = sin(35)/b
b*sin(120) = 68*sin(35) <<--- cross multiply
b = 68*sin(35)/sin(120)
b = 45.037013350222 <<--- use a calculator; this value is approximate
b = 45.0 <<--- round to the nearest tenth

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Do the same for side c
sin(A)/a = sin(C)/c
sin(120)/68 = sin(25)/c
c*sin(120) = 68*sin(25) <<--- cross multiply
c = 68*sin(25)/sin(120)
c = 33.1838323365404 <<--- use a calculator; this value is approximate
c = 33.2 <<--- round to the nearest tenth

4 0

3 years ago

Read 2 more answers

Factor the polynomial by its greatest common monomial factor.

Gwar [14]

Answer: 3b^4(b+5-6b^3)

Step-by-step explanation:

6 0

2 years ago