1. A) 5 (It would be B. because it does equal 4.09 but it has to be 5 because it is the greatest integer in all of them)
2. D) 10 (Just like 1. it would be B. also BUT 10 is the greatest integer you can have out of all of them)
3. A) 6 (Just like the other 2 problems at the top^ it would be C. if not for the fact it has a higher number.)
4. A) A value we can put in place of a variable (such as x) that makes the equation true.
Answer:
f(x)=1/2x-6
Step-by-step explanation:
Answer:
The answer is C
Step-by-step explanation:
An isosceles triangle has two angles that measure the same, so...
30 + 30 = 60
180 - 60 = 120
No
____________
45 + 45 = 90
180 - 90 = 90
No
____________
60 + 60 = 120
180 - 120 = 60
Yes
____________
90 + 90 = 180
No
Whats the expression so you can plug those numbers in.
Answer:
The answer is "
"
Step-by-step explanation:
Given:
Find critical points:
differentiate the value with respect of x:
![\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r} \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]](https://tex.z-dn.net/?f=%5Cto%20g%27%28x%29%3D%20%28x-e%29%5E3%20%5Cfrac%7Bd%7D%7Bdx%7De%5E%7Be-r%7D%20%2Be%5E%7Be-r%7D%20%20%5Cfrac%7Bd%7D%7Bdx%7D%28x-e%29%5E3%3D%28x-e%29%5E2%20e%5E%7B%28e-x%29%7D%20%5B-x%2Be%2B3%5D)
critical points 
![\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3](https://tex.z-dn.net/?f=%5Cto%20%28x-e%29%5E2%20e%5E%7B%28e-x%29%7D%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20e%5E%7B%28e-x%29%7D%5Cneq%200%20%5C%5C%5C%5C%5Cto%20%28x-e%29%5E2%3D0%5C%5C%5C%5C%20%5Cto%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20x%3De%5C%5C%5C%5C%5Cto%20x%3De%2B3%5C%5C%5C%5C%5Cto%20x%3D%20e%2Ce%2B3)
So,
The critical points of 
