The amount of money spent weekly on cleaning, maintenance, and repairs at a large restaurant was observed over a long period of
time to be approximately normally distributed, with mean μ = $597 and standard deviation σ = $39. (a) If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
Z = ( X - Mean ) / SD z = ( 646 - 597 ) / 39 z = 49/39 = 1.25 With the z-score table: for z = 1.25, p = 0.8944 ( probability that the cost will be lower than $646 ) 1 - 0.8944 = 0.1056 Answer: <span>The probabilit</span>y is 0.1056
