3 years ago

Rewrite using positive exponents. 4a^3b^-2 x^-8

Mathematics

1 answer:

____ [38]3 years ago

4 0

$a^{-n}=\dfrac{1}{a^n}\\\\4a^3b^{-2}=\dfrac{4a^3}{b^2}\\\\x^{-8}=\dfrac{1}{x^8}$

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