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podryga [215]
3 years ago
8

Rewrite using positive exponents. 4a^3b^-2 x^-8

Mathematics
1 answer:
____ [38]3 years ago
4 0
a^{-n}=\dfrac{1}{a^n}\\\\4a^3b^{-2}=\dfrac{4a^3}{b^2}\\\\x^{-8}=\dfrac{1}{x^8}
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