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3 years ago

Find the sum using estimation to the nearest dollar: $72.90+$15.45+$120.99

Mathematics

2 answers:

o-na [289]3 years ago

8 0

Answer: 209

Step-by-step explanation:

lord [1]3 years ago

7 0

Answer:

$209

Step-by-step explanation:

We use addition.

$72.90

$15.45

$120.99

__________

$209.34 (round to nearest dollar) = $209

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A teacher student committee consisting of 4 people is to be formed from 5 teachers and 20 students. Find the probability that th

antiseptic1488 [7]

Answer:

99.96%

Step-by-step explanation:

Given the information:

5 teachers

20 students

4 people in committee

=> the are 25 people in total

Hence, the total possible outcomes of all the members in the 4 committee:

$C^{4} _{25} = 12650$

They want us to find the probability that the committee will consist of at least one student, which means that

=(Total possible outcome - committee with no student) / Total possible outcomes

So we need to find the possible outcomes of committee with no student:

= $C^{4} _{5} =5$

=> the probability that the committee will consist of at least one student.

= (12650 - 5) / 12650

= 0.9996

= 99.96%

Hope it will find you well.

5 0

3 years ago

Mrs. Smith left a 15% tip for a dinner that cost $62.40. About how much tip did Mrs. Smith leave?

Veronika [31]

Given :- 

Mrs. Smith left a 15% tip for a dinner that cost $62.40.

To find :- 

About how much tip did Mrs. Smith leave?

Solution :- 

The tip is 15% of $62.40 .

• Calculating 15% of $62.40

$ 62.40 * 15%
$ 62.40 * 15/100
$ 9.36

4 0

3 years ago

Read 2 more answers

What is the product?( square root 3x+ square root 5) (square root 15x+ 2 square root 30)

hichkok12 [17]

$(\sqrt{3x}+\sqrt5)\cdot(\sqrt{15x}+2\sqrt{30})\\\\=(\sqrt{3x})(\sqrt{15x})+(\sqrt{3x})(2\sqrt{30})+(\sqrt5)(\sqrt{15x})+(\sqrt5)(2\sqrt{30})\\\\=\sqrt{(3x)(15x)}+2\sqrt{(3x)(30)}+\sqrt{(5)(15x)}+2\sqrt{(5)(30)}\\\\=\sqrt{45x^2}+2\sqrt{90x}+\sqrt{75x}+2\sqrt{150}\\\\=\sqrt{9x^2\cdot5}+2\sqrt{9\cdot10x}+\sqrt{25\cdot3x}+2\sqrt{25\cdot6}\\\\=\sqrt{9x^2}\cdot\sqrt5+2\sqrt9\cdot\sqrt{10x}+\sqrt{25}\cdot\sqrt{3x}+2\sqrt{25}\cdot\sqrt6$
$=3x\sqrt5+2\cdot3\sqrt{10x}+5\sqrt{3x}+2\cdot5\sqrt6\\\\=3x\sqrt5+6\sqrt{10}+5\sqrt{3x}+10\sqrt6$

3 0

3 years ago

Read 2 more answers

What is the answer to this?

nekit [7.7K]

Answer:

Step-by-step explanation:

Y= 1x^2 + 3x + 9

Y= Ax^2 + Bx + C

To determine which way a parabola opens just look at the coefficient (the number) of the x^2 - Always use the coefficient that is beside the x^2

So, if the coefficient A is positive the parabola is opening upward

if the coefficient A is negative the parabola is opening downward