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iogann1982 [59]
3 years ago
14

Tim has a recipe for chocolate mousse. The recipe is for 8 people. The recipe needs 200g of . Tim wants to make chocolate mousse

for 50 people. He buy bars of chocolate for the mousse .One bar of chocolate weights 150g. How many bars of chocolate does Tim need to buy? Please explain if possible how you get the answer
Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0
If the recipe needs 200g of chocolate bars, and that recipe feeds 8 people, you need to figure out how many times you'd have to make a recipe to feed 50 people.

50 is not a factor of 8, so we have to break the recipe down. if 200g of chocolate feeds 8 people, then it's safe to assume that 100g feeds 4 people, and 50g feeds 2 people. 

The closest you get to 50 without exceeding it by a factor of 8 is 6 x 8= 48. You'd be missing the chocolate for two people, all you have to do is add 50 grams of a chocolate bar.

You have to multiply each ingredient by 6 therefore everything is exactly the same, just amplified. 200 x 6 =1200, which means you'd need 1200g of chocolate bars + 50g to make a mousse for 50 people. 

Each chocolate bar has 150g, so now what you do is you get the 1250g and divide it by 150g. This will tell you the amount of chocolate bars you need to complete the recipe for 50 people. The answer is 8.33333, which means Tim will have to buy 9 chocolate bars.
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\text{The sum of } 1\frac{7}{10}  \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}

<em><u>Solution:</u></em>

Given that we have to find the sum of 1\frac{7}{10} \text{ and } 3\frac{3}{5}

<em><u>Let us first convert the mixed fractions to improper fractions</u></em>

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Then write the result on top of the denominator

Therefore,

1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}

Now we can add both the fractions

1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18}{5}

Make the denominators same

1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}

Now convert the fraction to mixed number

When we divide 53 by 10 , the remainder is 3

Therefore, write 5 as a whole number and and 3 as numerator and 10 as denominator

\frac{53}{10} = 5\frac{3}{10}

Thus the sum of given mixed fraction is 5\frac{3}{10}

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