An equation of line with a slope of 1/3 and containing the point (-4,7) is
y = 1/3 x + 25/7
In this question, we have been given
slope (m) = 1/3
and a point (-4, 7)
We need to find an equation of a line with a slope of 1/3 and containing the point (-4,7)
Using the formula for the slope-point form of equation of line,
y - y1 = m(x - x1)
y - 7 = 1/3(x + 4)
y - 7 = (1/3)x + 4/3
y = (1/3)x + 4/3 + 7
y = 1/3 x + 25/7
Therefore, an equation of line with a slope of 1/3 and containing the point (-4,7) is y = 1/3 x + 25/7
Learn more about the equation of line here:
brainly.com/question/24524587
#SPJ1
Answer:
1.11,1.23,2.13, 3.12
Step-by-step explanation:
You subtract normally inside the absolute value (the two bars):
-4-3 is -7
Since the negative is INSIDE the absolute, the answer will turn to a positive. Think of the bars as a jail cell for the negatives. Once the negatives are in there, only positive numbers will come out. So your answer is 7.
You have to divide 2029 by 2 to get how many marbles they divided equally. The answer is 2029÷2 = 1014 marbles.