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Veseljchak [2.6K]

2 years ago

5

Hi! If you have time, I am stuck on this problem. I don't get it. You need to find the net pay and I was wrong. Please help. No

need for really big explanation

1 answer:

ElenaW [278]2 years ago

4 0

Answer:

Your pay before taxes are $292.50 (gross earnings)

So your total tax is $31.55 (Total deductions)

After the tax is deducted the pay is $260.95 (net pay)

The rest of the answers to the chart are below and bolded

Step-by-step explanation:

Okay simple explanation

you need to find total and the tax for each one by multiply by it’s percent

THe total you cna get of course form multiply 30 hours by 2.75 per hour so you’d get 292.50

Now to find the tax just multiply 292.50 by the percents given and make sure to move those decimal Places

292.50*0.1=29.25 (federal tax / 10%)

292.50*0.062=1.86 (ss tax / 6.2%)

292.50*0.0145=0.435 {round that to nearest penny 0.44} (Medical care/ 1.45%)

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

Can someone solve this?

ladessa [460]

First question:

Recall that $\cos^2x+\sin^2x=1$ and $\sqrt{x^2}=|x|$ for all $x$ . So

$\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|$

$\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|$

For $0$ , we expect both $\cos x>0$ and $\sin x>0$ (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, $|x|=x$ if $x>0$ .

So we have

$\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}$

making H the answer.

Second question:

C is always true, because the inequality reduces to x > y.

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3 years ago

If the line segment at right is subdivided

Stells [14]

Answer:

50

Step-by-step explanation:

75 dived into 3 parts can also be written as 75/3. 75/3 is 25 making each part worth 25. 2 segments are included in the marked portion so its 50 or (25 + 25)

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2 years ago

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(of an increase) becoming more and more rapid.

"the social security budget was rising at an exponential rate"

Step-by-step explanation:

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3 years ago

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Answer:

m=-1/2

Step-by-step explanation:

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3 years ago