We have to find the volume of oblique cone. An oblique cone is a special type of cone in which the apex is not located directly above the center of the circular base, so it looks like a slanted cone.
Volume of oblique cone = ![\frac{1}{3} \Pi r^{2}h](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20%5CPi%20r%5E%7B2%7Dh%20)
where 'r' is the radius and 'h' is the height.
Here r = 6 cm and h = 10 cm
Volume = ![\frac{1}{3} (\Pi (6)^{2} \times 10)](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20%28%5CPi%20%286%29%5E%7B2%7D%20%5Ctimes%2010%29%20)
= ![\frac{360\Pi }{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B360%5CPi%20%7D%7B3%7D%20)
= ![120\Pi cm^{3}](https://tex.z-dn.net/?f=%20120%5CPi%20cm%5E%7B3%7D%20)
So, the volume of the given oblique cone is
.
Option 4 is the correct answer.
Answer:i simplified it and got 9 so 3 to the second power
Step-by-step explanation:
Answer:
y = x + 1.8
Step-by-step explanation:
Below is the solution:
A(final)=16cm^2 ds/dT=6 da/dT=?
<span>A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm </span>
<span>da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm)
</span>
<span>Answer should be da/dT=48cm^2/sec
</span>
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Answer:
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