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3 years ago

Expand the following logarithmic expression.

Mathematics

1 answer:

Nat2105 [25]3 years ago

5 0

Answer:

log5(8)+Log5(\sqrt{t})-log5(v)

Step-by-step explanation:

coolio

You can use the log rules

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Which expression is equivalent to 3(sqrt)125x^6y^15z^3?

Kay [80]

B. would be the correct choice here

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3 years ago

Read 2 more answers

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

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2 years ago

Jeremy’s pay started at a $500 per week. Every year his pay will increase by $25 per week. Write an equation that models his wee

algol [13]

Answer:

W = 500 + 25x

Step-by-step explanation:

Jeremy’s pay started at $500 per week. Every year his pay will increase by $25 per week.

Now, after x years his pay per week will increase by $(25x).

Therefore, if we model the weekly payment of Jeremy by an equation, then it will be given by

W = 500 + 25x

where W is his weekly payment after x years. (Answer)

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3 years ago

Calculate the product below and give your answer in scientific notation.

valentinak56 [21]

This should be the answer 3.0x10^-5

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1 year ago

Please answer right.

boyakko [2]

Answer:

The answer is A. Good Luck!

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2 years ago