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Novay_Z [31]
3 years ago
15

Simplify. -1/2X+3-4X+5+3/2X x

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:-3x+8

Step-by-step explanation:

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The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
A random sample of 41 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.55 per car. The p
Rashid [163]

Answer:

19.55\pm2.145

Step-by-step explanation:

We use the equation \bar x\pm z^*\sigma/\sqrt n, where \bar x=19.55, \sigma=6.33, n=41, and z^*=2.17. We obtain z^* from the z-score of a 0.97 confidence level.

8 0
2 years ago
Prove that one of every three consecutive positive integer is divisible by 3
Inessa05 [86]
Hello : 
all n in N ; n(n+1)(n+2) = 3a    a in  N  or : <span>≡ 0 (mod 3)
1 ) n </span><span>≡ 0 ( mod 3)...(1)

     n+1 </span>≡ 1 ( mod 3)...(2)
      n+2 ≡ 2 ( mod 3)...(3)
by (1), (2), (3)  : n(n+1)(n+2) ≡ 0×1×2   ( mod 3)   : ≡ 0 (mod 3)
2) n ≡ 1 ( mod 3)...(1)

     n+1 ≡ 2 ( mod 3)...(2)
      n+2 ≡ 3 ( mod 3)...(3)
by (1), (2), (3)  : n(n+1)(n+2) ≡ 1×2 × 3  ( mod 3)   : ≡ 0 (mod 3) , 6≡ 0 (mod)
 3) n  ≡ 2 ( mod 3)...(1)

     n+1 ≡ 3 ( mod 3)...(2)
      n+2 ≡ 4 ( mod 3)...(3)
by (1), (2), (3)  : n(n+1)(n+2) ≡ 2×3 × 4  ( mod 3)   : ≡ 0 (mod 3) , 24≡ 0      (mod3)
5 0
3 years ago
I need help plz help me
irinina [24]
The answer is A
i think so but i might be wrong 
sorry if i am.
7 0
3 years ago
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An airplane flies 600 km in 1 hour. What is it’s average speed in kilometers per hour.
Gnoma [55]
600km??? Because it’s travelling 600km and hour so it’s average is 600km and hour
6 0
3 years ago
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