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vredina [299]
3 years ago
11

In a certain chemical, the ratio of zinc to copper is 4 to 17. A jar of the chemical contains 357 grams of copper. How many gram

s of zinc does it contain?
Mathematics
2 answers:
12345 [234]3 years ago
6 0

Answer:84

Step-by-step explanation:

alex41 [277]3 years ago
6 0
This is your perfect answer.


Moles Cu = 300 g x 1 mol Cu/63.55 g = 4.72 moles Cu
Moles Zn = 4/15(4.72) = 1.26 moles
mass Zn = 1.26 moles x 65.38 g/mol = 82.3 g
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Jean throws a ball with an initial velocity of 64 feet per second from a height of 3 feet. Write an equation and answer the ques
Ganezh [65]
<h2>a. What is your equation?</h2>

This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:

h(t)=-\frac{1}{2}gt^2+v_{0}t+h_{0}

Where:

h(t): \ height \ at \ any \ time \\ \\ g: \ acceleration \ due \ to \ gravity \ 9.8m/s^2 \ or \ 32.16ft/s^2 \\ \\ v_{0}= \ Initial \ velocity

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h(t)=-\frac{1}{2}(32.16)t^2+(64)t+3 \\ \\ \boxed{h(t)=-16.08t^2+64t+3}

<h2>b. How long will it take the rocket to reach its maximum height?</h2>

The rocket will reach the maximum height at the vertex of the parabola described by the equation h(t)=-16.08t^2+64t+3. Therefore, our goal is to find t at this point. In math, a parabola is described by the quadratic function:

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So the x-coordinate of the vertex can be calculated as:

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From our equation:

a=-16.08 \\ \\ b=64 \\ \\ c=3

So:

t=-\frac{64}{2(-16.08)} \\ \\ \boxed{t=1.99s}

So the rocket will take its maximum value after 1.99 seconds.

<h2>c. What is the maximum height the rocket will reach?</h2>

From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by h(1.99). Thus, we can find this as follows:

H_{max}=h(1.99)=-16.08(1.99)^2+64(1.99)+3 \\ \\ \boxed{H_{max}=66.68ft}

So the maximum height the rocket will reach is 66.68ft

<h2>d. How long is the rocket in the air?</h2>

The rocket is in the air until it hits the ground. This can be found setting h(t)=0, so:

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We can't have negative value of time, so the only correct option is t_{1}=4.0264 and rounding to the nearest hundredth we have definitively:

\boxed{t=4.03s}

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