Evaluate the expression, using the given value of the variable z÷3-5z+4 (z-2) when z=12

1 answer:

7 0

12/3-5(12)+4(12-2)
pemdass
12-2=10

12/3-5(12)+4(10)
divide or multiply
12/3=4
5(12)=60
4(10)=40

we now have
4-60+40
add
-16

You might be interested in

HHEELLPP ME GET A GOOD GRADE

muminat

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
A(\stackrel{x_1}{2m}~,~\stackrel{y_1}{2n})\qquad 
C(\stackrel{x_2}{2p}~,~\stackrel{y_2}{2r})
\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{2p+2m}{2}~~,~~\cfrac{2r+2n}{2} \right)\implies \left( \cfrac{\underline{2}(p+m)}{\underline{2}}~~,~~\cfrac{\underline{2}(r+n)}{\underline{2}} \right)
\\\\\\
~~~~~~~~[(p+m)~,~(r+n)]$

6 0

2 years ago

You have a new pool and want to know its volume. The pool is 5 feet deep and has a radius of 7 feet. How much water can a pool h

leva [86]

Answer:

769.6902 (or 769.3) cubic feet of water

Step-by-step explanation:

πr^2

r = 7

5 x π(7)^2 = 769.6902 (or 769.3 using 3.14)

5 0

2 years ago

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. Whe

kherson [118]

Answer:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: