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ddd [48]
2 years ago
15

Pick a user for me (im so indecicive) most helpful answer gets brainlist ofc also lots of points, yw!

Mathematics
2 answers:
OleMash [197]2 years ago
7 0

Answer:

I would say the 1st one but that's just me

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST I REALLY WANT TO LEVEL UP

Tatiana [17]2 years ago
6 0

Answer:

hello im backk

Step-by-step explanation:

just wanted that person to get brainlest <3

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sandy had 3.8 points in the quiz game. she missed 5 questions losing 1 point each time how many points did she have at the end
telo118 [61]

Answer:

-1.2

Step-by-step explanation:

3.8-5=-1.2

lmk if this is right

hope it helped

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Given: AABC-ADEF
Jlenok [28]
The answer is B because those triangles are congruent
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Write 7x^2 -4 + 6x^3 -4x -x^4 in standard form
Nata [24]

-x⁴+ 6x³- 7x²- 4x - 4

Order from least to greatest exponent (the variable, which is x in this case, is always first by the way in terms of order, then integers). This point of this problem is essentially to just rearrange the original equation.

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Send answer really need it
Travka [436]

Answer:

DO U KNOW HOW TO GET MORE POINTS?

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha
s2008m [1.1K]

Answer:

Part 1) The  lateral area of the cone is LA=2\pi\ cm^{2}

Part 2) The lateral surface area of the cylinder is LA=36\pi\ cm^{2}

Part 3) The surface area of the crayon is SA=41.50\pi\ cm^{2}

Step-by-step explanation:

Part 1) Find the  lateral area of the cone  

The lateral area of the cone is equal to

LA=\pi rl

we have

r=1\ cm

l=2\ cm

substitute

LA=\pi (1)(2)

LA=2\pi\ cm^{2}

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

LA=2\pi rh

we have

r=1.5\ cm

h=12\ cm

substitute

LA=2\pi (1.5)(12)

LA=36\pi\ cm^{2}

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

A=\pi[r2^{2}-r1^{2}]

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

A=\pi[1.5^{2}-1^{2}]

A=1.25\pi\ cm^{2}

<em>Find the area of the top base of the cylinder</em>

A=\pi(1.5)^{2}=2.25\pi\ cm^{2}

<em>Find the surface area</em>

SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}

8 0
3 years ago
Read 2 more answers
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