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satela [25.4K]
3 years ago
6

Hi, please help with the exponent rules and explain them to me I included a picture!!!

Mathematics
1 answer:
kifflom [539]3 years ago
3 0
Message me and I will help you :)
You might be interested in
Help please now help dont be childish will banned ​
belka [17]

Answer:

X, process, y

-2, 3(-2), -6

-1, 3(-1), -3

0, 3(0), 0

1, 3(1), 3

2, 3(2), 6

X = -2, -1, 0, 1, 2,

Y = -6, -3, 0, -3, -6

Step-by-step explanation:

Coordinates for the graph: (-2,-6), (-1,-3), (0,0), (1,3), (2,6)

Graph is the image I added onto this.

Solving for Y below:

3(-2)= -6

3(-1)= -3

3(0)= 0

3(1)= 3

3(2)= 6

Hope this helps.

5 0
2 years ago
5(x+4)= -2(-4-x)+3 <br> what is the answer?
lianna [129]

Answer:

x = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

5(x + 4) = -2(-4 - x) + 3

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   5x + 20 = 8 + 2x + 3
  2. Combine like terms:                   5x + 20 = 2x + 11
  3. Subtract 2x on both sides:        3x + 20 = 11
  4. Subtract 20 on both sides:        3x = -9
  5. Divide 3 on both sides:              x = -3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    5(-3 + 4) = -2(-4 - -3) + 3
  2. Simplify:                        5(-3 + 4) = -2(-4 + 3) + 3
  3. Add:                              5(1) = -2(-1) + 3
  4. Multiply:                        5 = 2 + 3
  5. Add:                              5 = 5

Here we see that 5 does indeed equal 5. ∴ x = -3 is a solution of the equation.

And we have our final answer!

5 0
3 years ago
Read 2 more answers
James wants to promote his band on the internet. Site A offers website hosting for $4.95 per month with a $49.95 startup fee. Si
cupoosta [38]

Answer:

Part 1) see the procedure

Part 2) 4.95x+49.95 < 9.95 x

Part 3) x > 9.99\ months

Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

Step-by-step explanation:

Part 1) Define a variable for the situation.

Let

x ------> the number of months

y ----> the total cost monthly for website hosting

Part 2) Write an inequality that represents the situation.

we know that

Site A

y=4.95x+49.95

Site B

y=9.95x

The inequality that represent this situation is

4.95x+49.95 < 9.95 x

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

4.95x+49.95 < 9.95 x

Subtract 4.95x both sides

4.95x+49.95-4.95x < 9.95 x-4.95x

49.95 < 5x

Divide by 5 both sides

49.95/5 < 5x/5

9.99 < x

Rewrite

x > 9.99\ months

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.

The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

4 0
3 years ago
A. Find three rational numbers between 1/4 and 0.25 repeating
harina [27]
A. 0.250006, 0.250007, 0.250008
b. 0.3330001, 0.3330002, 0.3330003
4 0
2 years ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
aksik [14]

Answer:

the expected value of this raffle if you buy 1​ ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at​ $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as​ follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Thus; the amount and the corresponding probability can be computed as:

Amount                            Probability

$500 -$1 = $499                1/5000

$300 -$1 = $299                3/5000

$50 - $1 = $49                     5/5000

$5 - $1 = $4                      20/5000

-$1                                   1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is  as follows:

E(x) = \sum x  * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000}  + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016  + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

Thus; the expected value of this raffle if you buy 1​ ticket = -0.65

7 0
3 years ago
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