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jolli1 [7]
3 years ago
7

Which of the following equations is of the parabola whose vertex is at (4, 3), axis of symmetry parallel to the y-axis and focus

at (4, -3)?
A.) y+3=1/24 (x+4)^2
B.)y-3=-1/24 (x-4)^2
C.)x-4=-1/24 (y-3)^2
Mathematics
1 answer:
Molodets [167]3 years ago
4 0

Answer:

B.

Step-by-step explanation:

First thing to determine is how this parabola opens.  Up or down? Or left or right?  

*We see that the axis of symmetry is a line parallel to the y-axis; therefore, the axis of symmetry is an x =    line, making this an up or down parabola.  Now we need to determine how everything else all fits in.

The standard form of this type of parabola is

4p(y-k)=-(x-h)^2

where p is the distance between the vertex and the focus.  If the vertex has a y coordinate of 3, and the focus has a y coordinate of -3, the vertical distance between those 2 numbers is 6.  Therefore, p = 6.  Filling in then:

4(6)(y-3)=-(x-4)^2

and 24(y-3)=-(x-4)^2

Dividing both sides by 24 gives you what you are looking for:

y-3=-\frac{1}{24}(x-4)^2

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Thus, \hat p=\frac{4}{39} =0.10256

Now, for 90% confidence level, from the table we know that Z=1.645.

The formula for the interval range of proportion of students is :

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Plugging in the values we get:

p=0.10256\pm 1.645\sqrt{\frac{0.10256(1-0.10256)}{39}}=0.10256\pm 0.04858=0.15114, 0.05398

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2 years ago
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