3 years ago

Find the median 13,22,21,25,15

Mathematics

2 answers:

lord [1]3 years ago

8 0

After arranging the numbers: (13, 15, 21, 22, 25) your median (aka middle number) would be 21

Ber [7]3 years ago

7 0

Arrange these numbers :

13, 15, 21, 22, 25

So, the median is 21

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Random Questions To Answer For Points.

Fantom [35]

Answer:

The rate is the distance divided by the time.

60 feet in 10 seconds = 60 ft / 10 sec = 6 ft / sec

42 feet in 6 seconds = 42 ft / 6 sec = 7 ft / sec <--- We have a winner!

Step-by-step explanation:

6 0

3 years ago

Who knows the area of this ? #struggleatmath

photoshop1234 [79]

I think it’s 6. There are 4 squares and 4 triangles. 2 triangles put together turn into a square, so that would make 2 extra squares. 4+2=6.

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3 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$